$$ \int_{-\infty}^{\infty} e^{-x^2}dx = \sqrt(\pi)...
\( \int_{-\infty}^{\infty} e^{-x^2}dx = \sqrt(\pi) \)
\(\ce{ $\frac{[\ce{A}]}{[\ce{B}]}$$\Delta H_\ce{f}^\ominus$ }\)
Zuletzt geändert: Freitag, 7. August 2020, 20:02
\( \int_{-\infty}^{\infty} e^{-x^2}dx = \sqrt(\pi) \)
\(\ce{ $\frac{[\ce{A}]}{[\ce{B}]}$$\Delta H_\ce{f}^\ominus$ }\)